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NEW QUESTION 44
以下关于 PBR 说法中,正确的是 _________
- A. 通过 PBR ,可以设置路由协议引入的路由属性
- B. PBR 可基于到达报文的源地址进行路由选择
- C. PBR 不可基于到达报文的长度进行路由选择
- D. PBR 是一种依据用户制定的策略进行路由选择的机制
Answer: B,D
NEW QUESTION 45
E 如图所示, RTB 与 RTC 各从 RTD 学到 EBGP 路由 N , RTB 缺失 LOCAL_PREF 设置为 200 , RTA 与 RTB 、 RTC 之间通过 loopback 建立 IBGP 邻居关系, RTA 路由表中,只有 N 、 RTB 与 RTC 的 loopback 、 RTA 自身直接路由,如果 RTB 因为电源故障宕机,请问在 RTA 上,路由 N 能否马上切换到 RTC?
- A. 可以,因为 RTA 和 RTB 的邻居关系中断, RTA 立刻切换到 RTC
- B. 不可以,因为 RTA 和 RTB 的邻居关系要等到 holdtime 超时才能中断,大概需要 3 分钟才能切换过去
- C. 不可以,因为 RTA 与 RTB 是通过 loopback 地址建立 IBGP 邻居关系的,如果改进互连接口可以上切换
- D. 可以,因为指向 RTB 的那条路由 N 下一跳不可达, RTA 立刻切换到 RTC
Answer: D
NEW QUESTION 46
如图所示 IS-IS 网络中, RTA 、 RTB 、 RTC 配置如下:
RTA]isis
RTA-isis-1]is-level level-1
RTA-isis-1]network-entit01.1111.1111.1111.00
RTA-isis-1]interface serial 2/0
RTA-Serial2/0]isis enable 1
RTB]isis
RTB-isis-1]is-level level-1
RTB-isis-1]network-entit01.2222.2222.2222.00
RTB-isis-1]interface serial 1/0
RTB-Serial1/0]isis enable 1
RTB-Serial1/0]interface Ethernet 0/0
RTB-Ethernet0/0]isis enable 1
RTC]isis
RTC-isis-1]is-level level-1
RTC-isis-1]network-entit01.3333.3333.3333.00
RTC-isis-1]interface Ethernet 0/0
RTC-Ethernet0/0]isis enable 1
RTC-Ethernet0/0]interface Ethernet 0/1
RTC-Ethernet0/1]isis enable 1
各路由器路由稳定后, RTA 上 IS-IS 路由 192.168.3.0/24 的开销是 ______ 。
- A. 0
- B. 1
- C. 2
- D. 3
- E. 4
Answer: E
NEW QUESTION 47
IS-IS 报文中 IP Internal ReachabilitInformation CLV 的作用是 ______ 。
- A. 携带 IP 前缀信息,即 IP 路由信息
- B. 携带 IS 的 Stem-ID 信息
- C. 携带使能 IS-IS 接口的 IP 地址信息
- D. 携带 IS 的区域号
Answer: A
NEW QUESTION 48
组网如图所示, RTA 、 RTB 位于 AS 1001 , RTC 、 RTD 、 RTE 位于 AS 1002 , AS 1001 向 AS 1002 发布 BGP 路由 11.11.11.0/24 , RTC 、 RTD 的 BGP 主要配置如下,如果 RTE 、 RTC 的互联链路中断, RTE 访问 11.11.11.0/24 网段,优先经过哪条广域链路 ?
RTC]
bgp 1002
preference 20 170 200
peerRTA as-number 1001
peerRTD as-number 1002
peerRTA route-policsetmed import
route-policsetmed permit node 10
applcost 100
RTD]
bgp 1002
preference 20 170 200
peerRTB as-number 1001
peerRTC as-number 1002
peerRTA route-policsetmed import
route-policsetmed permit node 10
applcost 200
- A. 优先经过广域链路二,因为 RTD 的 MED 200>RTC 的 MED 100 。
- B. 优先经过广域链路一,因为 RTC 的 MED 100<RTD 的 MED 200
- C. 优先经过广域链路二,因为 RTD 上 eBGP 路由优先。
- D. 优先经过广域链路一,因为 RTC 上 eBGP 路由优先。
Answer: C
NEW QUESTION 49
……
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